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  • Conversion of Specific fuel Consumptions

    Discussion in 'Calculations' started by hemcrop, Aug 8, 2011.

    1. hemcrop

      hemcrop New Member

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      Dear All,

      I have Data Sheet of a Diesel Engine of capacity 1650KVA/ 1320KW. The fuel Consumption of Engine is given in terms of g/kWh for specific loads as shown below.

      Specific Fuel Consumption (be) - 100% FSP - 193 g/kWh
      Specific Fuel Consumption (be) - 75% FSP - 194 g/kWh
      Specific Fuel Consumption (be) - 50% FSP- 201 g/kWh
      Specific Fuel Consumption (be) - 25% FSP- 228 g/kWh

      please tell me how to convert above consumptions values from g/kWh to liters.
      Is there any formula involved to convert it/

      Cheers,

      Hemcrop
       
    2.  
    3. mihai

      mihai New Member

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      Hy!

      You can use this formula:
      CI=c x P x 1/ro

      where: c - specific consumption (g/kWh)
      P - power (kW)
      ro - fuel density (kg/m3)
      Your result CI (fuel consumption in time) will be in m3/h. (x 1000 for liters/h)

      Cheers,
      Mihai
       
    4. hemcrop

      hemcrop New Member

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      Thanks A lot mihai. This Definitely going to help me a lot.

      Cheers
      Hemcrop
       
    5. mihai

      mihai New Member

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      P - is power for a specific load (25%, 50%, 75%, 100%), in your case, 100% is 1320kW.

      So, your consumption for one hour (if, for example, you are using gasoline ro=835kg/m3):

      CI (100%) = 0,193kg/kWh x 1/835kg/m3 x 1320kW = 0,305 m3/h = 305 l/h

      cheers,
      Mihai
       
    6. brijs

      brijs Member

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      Hi all,
      Thanks mihai, The formula CI=c x P x 1/ro is absolutely correct.
       
    7. leenko

      leenko New Member

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      What is the RO of Diesel?
       

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