Dear All, I have Data Sheet of a Diesel Engine of capacity 1650KVA/ 1320KW. The fuel Consumption of Engine is given in terms of g/kWh for specific loads as shown below. Specific Fuel Consumption (be) - 100% FSP - 193 g/kWh Specific Fuel Consumption (be) - 75% FSP - 194 g/kWh Specific Fuel Consumption (be) - 50% FSP- 201 g/kWh Specific Fuel Consumption (be) - 25% FSP- 228 g/kWh please tell me how to convert above consumptions values from g/kWh to liters. Is there any formula involved to convert it/ Cheers, Hemcrop

Hy! You can use this formula: CI=c x P x 1/ro where: c - specific consumption (g/kWh) P - power (kW) ro - fuel density (kg/m3) Your result CI (fuel consumption in time) will be in m3/h. (x 1000 for liters/h) Cheers, Mihai

P - is power for a specific load (25%, 50%, 75%, 100%), in your case, 100% is 1320kW. So, your consumption for one hour (if, for example, you are using gasoline ro=835kg/m3): CI (100%) = 0,193kg/kWh x 1/835kg/m3 x 1320kW = 0,305 m3/h = 305 l/h cheers, Mihai