Discussion in 'The main mechanical design forum' started by Kohlkopf, Oct 29, 2013.
Initially the gear will turn counter clockwise to create the equilibrium. Then it will stop.
Down. As the gear rotates, the height of the 20kg weight will not change, so it's not a factor.
Assuming the teeth can't slip, the system is equivalent to a 10kg weight on the left and none on the right, same net moment applied to the gear/pulley.
The distance between the axis of rotation of the gear and the rack should be known though to determine the force downwards on the pulley due to gravity...
How is the gear shaft supported? Initially it seems the whole thing should just drop in a pile.
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