• Welcome to engineeringclicks.com
  • Force required to pull a 5 ton pipe...

    Discussion in 'Calculations' started by daveeboi, Sep 11, 2010.

    1. daveeboi

      daveeboi New Member

      Joined:
      Sep 2010
      Posts:
      1
      Likes Received:
      0
      how do i calculate the force required to pull a 5 ton pipe along 10 idle pipe converyors, assuming that the pipe will force the rotator units to turn as the pipe is pulled, therefore building up very slight momentum?

      I have no idea where to start??
       
    2.  
    3. maniacal_engineer

      maniacal_engineer Well-Known Member

      Joined:
      Jul 2009
      Posts:
      137
      Likes Received:
      0
      Start with F=MA IOW force = mass times acceleration
      or, for the rollers torque = J alpha IOW torque equals polar moment times angular acceleration
      also torque equals force times the radius at which it acts (this allows you to add the linear load of the pipe to the angular load of the rollers)
      Polar moment about an axis is the integral of mass time the distance to the axis squared, ove rthe entire volume of the mass.

      Go to a physics book or a dynamics book. Make sure to account for friction and other minor losses.
       

    Share This Page