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• # How to find the required material thickness against Impact Load

Discussion in 'Members only subforum' started by Nagaraju, Sep 28, 2016.

1. ### NagarajuNew Member

Joined:
Sep 2016
Posts:
3
0
Hello
I am Nagaraju,working as mechanical design engineer. In one of my project i need to find the load induced on the component while dropping the object from 1 m height on the rigid ground floor.
Component details are here:
Material : Sheet Metal
Length: 300 mm
Width : 175 mm
Height : 10 mm
Drop Height: 1 m
Can anyone help me to find out the max load acting on the component (after impact) and also how can i find the material thickness required to withstand that load.
But i found the Max load value through the formula:a^2 = (kv1^2)/(2m)
where k = stiffness of the material
v = velocity after impact
m = mass of the object.
a = acceleration after impact.
so Force induced can be F = mxgxa N.

Note: I found the stiffness of the materiel through simulation. (Apply 100N force and obtain the deflection value 0.1578 mm so K can be load / deflection).
Pls also check whether this approach is correct.
I

Last edited: Sep 28, 2016
2.
3. ### Ganesh MoorthiMember

Joined:
Nov 2016
Posts:
13
0
Hi Nagaraju,

Kinetic energy = Impact force x distance travelled after impact.

Kinetic energy = 1/2 * m * v^2

Velocity = (2*g*h)^0.5

You need to know distance travelled after impact, The properties of impact surface(Restitution coefficient) decides this distance and the impact time.

So, Impact force can be calculated as Kinetic energy / distance travelled after impact.

Hope this helps... My advice is to perform this calculation using impact simulation.