Wonderful to have a forum that might be able to help me out. I have a requirement for a shear pin and need to know what material would be needed to achieve these results. I am into manufacturing so my expertise is not in material strength as far as testing is concerned. Here is what I have to work with. Known Material is not locked down, but must meet a double shear strength of 2750 lbs. +/- 200 lbs. We can size the dia such that we get the correct shear value. We want a material that has the yield strength no more than 20% less than ultimate. We are looking for a pin that is .156 or .125 in diameter Thank you in advance to anyone that can calculate this for me. Does the material need heat treating, type of material and size is what I'm looking for. Thank you, Dann
U can use cast iron material i guess and donot perform heat treatment that makes it hard and brittle in your case the pin shouldnt be briitle i think this will do
2750 double shear = 1375 single shear .125 dia area = .0123 inÂ², 111789 psi .15625 dia area = .0192 inÂ², 71615 psi At those stress levels a low alloy steel like 4130 or 4140, hardened as appropriate, would probably work fine.
Could you please specify what do you mean with double shear stress? Torsional or pure shear stress or mounted in a base producing two shear stress and the conditions enviromental, sports everything possible. As easy it seems the design of a simple pin its important to clarify your conditions, and what do you want that pin to do?