Hi, I am facing for some time a problem regarding tolerances and fits, leading me to look for an answer in the correspondig books, but, unfortunately, I haven't found one. I would be happy if someone could help me with an answer or even with a book reference, which would clarify the problem. Therefore, the problem looks like this: Given a 10.1 mm hole nominal size and a 10 mm shaft nominal size, it is required to find hole's and shaft's tolerated dimension for wich: a ) The maximum clearence must be by tenths order (i.e. 0.1, 0,2 ... ). b ) The minimum interferece must be by tenths order (i.e. 0.1, 0,2 ... ). Observation: According to fit definition - mating two parts can be done only between parts having the same nominal size. My attention was drew by the different nominal size value of the parts in this present case. So, do the two nominal sizes still subject to fit definition? If they do, then why they do, and how the problem can be solved? If you have any unclarities, please, feel free to adress them! Thank you for your time!

Hihasdoiesopatru, Pl.check this link contain online calculation for fits: http://www.caunoi.info/home/online-calculator/fits

Hello, that link doesn't work, you can try with another: http://www.mechtoday.info/calculation-of-fits.html

I think fits could still apply with different nominal diameters. Remember, the nominal is just a number. It doesn't really mean anything on it's own. What is the difference between 10.0 +.2/-0 and 10.1 +/- .1? Nothing, really. You are being asked to think just slightly out of the box. You're going to have to find an oversized shaft diameter, and/or an undersized hole diameter that will give you what you want.

the nominal with its tolerance defines the zone it falls into during manufacturing with normal distribution, if the 2 zones have interference, they can be assembled together