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    Discussion in 'Calculations' started by salman22, Jan 8, 2020.

    1. salman22

      salman22 New Member

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      Simply I need to calculate the torque required to move this solar tracker in the attachment assuming that i know every part's weight. What is the criteria should i follow?
       

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    3. Erich

      Erich Well-Known Member

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      Estimates of friction at all joints,
      Rate of acceleration desired as it starts up.
      What loads does wind have on the structure?

      Hint start with a free body diagram...……..
       
    4. jasonmeur

      jasonmeur New Member

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      Thank its Realy helpful...
       
    5. shachmat

      shachmat New Member

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      When i selecting a motor I'm checking all the moments in the system @ each angle and literally build the movement profile.
      After that its easy to understand what is the required "continues moment and what is the peak moment.
      Mt=F*L for movement.
      Mt= I[Kg*m^2] × alfa[rad/sec^2].for acceleration.

      Here is a good guide for motor selecting:
      https://www.machinedesign.com/motors-drives/article/21831643/how-to-pick-motors-for-linear-motion.

      Try to think about direct drive instead of spour gear
      Good luck
       
    6. Oilytrunk

      Oilytrunk Well-Known Member

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    7. Justcurioustwo

      Justcurioustwo Well-Known Member

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      Attached is a drawing of a machine that produces 118,428 foot pounds of force traveling at a speed of three (3) feet per second.

      How can I convert this to torque and then to potential electric output?
       

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    8. Justcurioustwo

      Justcurioustwo Well-Known Member

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    9. Erich

      Erich Well-Known Member

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      Units of force are pounds or Newtons.
      Foot-lbs are units of Torque or energy, not force.
      Clarify what you have.
       
    10. s.weinberg

      s.weinberg Well-Known Member EngineeringClicks Expert

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      What he has is a thoroughly debunked basic, run-of-the-mill, perpetual motion machine.
       
    11. Justcurioustwo

      Justcurioustwo Well-Known Member

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      Thanks for your clarification.

      Do you agree with the following.

      To determine the SeaEngine's potential energy output I have to determine the value of two (2) things-

      (1) energy it takes to compress 40,000 cubic feet of air down to 2,666.66 cubic feet in watts.

      (2) energy output of 118,428 foot pound in watts.

      If (watts-2)'s output is greater than (watts-1), then the SeaEngiine is producing useful work.
      I believe my drawing proves that the SeaEngine is producing useful work.
      :)-
       

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